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[Solved] sin2x+cosx=0

Given equation: sin2x+cosx=0, or 2sinxcosx+cosx=0, or cosx(2sinx+1)=0 ⇒cosx=0 or 2sinx+1=0. If cosx=0 then x=(2n+1)π2, where n∈z, and 2sinx+1=0,⇒sinx=− ...Read more

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https://www.doubtnut.com/qna/how-will-you-convert-...

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How many grams of NaBrO should be added to 1.00 L ...

How many grams of NaBrO should be added to 1.00 L of 0.200 M HBrO to form a buffer with a pH of 8.80? Ka for HBrO = 2.5 x10–9. More from this Exercise.Read more

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K2Cr2O7 + SO2 + H2SO4 ⇒ Cr2SO43 + K2SO4 + H2ONOTE

K2Cr2O7 + SO2 + H2SO4 ⇒ Cr2SO43 + K2SO4 + H2ONOTE: Please explain the way you solve it in detail that would be really helpful. More from this Exercise.Read more

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Na2SO4 and Na2S can be distinguished from each other by ...

Na2SO4 and Na2S can be distinguished from each other by using : A conc.H2SO4 B acidified KMnO4 solution C sodium nitroprusside solution D cadmium acetate ...Read more

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A - B - C - , (sinA+sinB+sinC)(sinA+sinB-sinC)=3sinAsinB then

To solve the problem step by step, we will start from the given equation and use the sine rule to express the sines in terms of the sides of the triangle.

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