Fiind all solutions at interval [0,2pi] sin^2x - cos^2x = 0

The tangent function is negative in the second and fourth quadrants. To find the second solution, subtract the reference angle from π π to find the solution in ...Read more

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General Solution of sin(2x)-cos(2x)=0 [closed]​​ This question does not meet Mathematics Stack Exchange guidelines. It is not currently accepting ...Read more

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I was trying to solve the equation: sin(2x) = -cos(2x), but I managed to do it incorrectly, like this: Using the unit circle, I get the incorrect solutions.Read more

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The solutions to the equation sin2x - cos2x = 0 on the interval [0, 2π) are {𝜋/4, 3𝜋/4, 5𝜋/4, 7𝜋/4}.Read more

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0 = sin^2 - cos^2 = sin^2 - ( 1 - sin^2) = sin^2 - 1 + sin^2 = 2sin^2 - 1 sin^2 = 1/2 sin = +or- sqrt(2)/2 X=Read more

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sin^2(x) - cos^2(x) = 0 (given) => sin^2x = cos^2x tan^2x=1 ..... (i) => tanx=±1 => x=tan−1(±1) Now, x=tan−1(1)=nπ+π/4 in general Also, ...

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Principal solutions at the equation sin 2x + cos 2x = 0, where π < x < 2 π are ______. Options. 7 ⁢ π 9 , 1 ...Read more

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The final solution is all the values that make 4sin3(x)cos(x)=0 4 sin 3 ( x ) cos ( x ) = 0 true. Consolidate the answers.Read more

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